a grinding wheel starts from rest and attains a constant angular acceleration of 5.0 rad s—². calculate the acceleration at a point 1.0m from the axis at t=6.0s
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angular acceleration α = 5.0 rad/s/s
linear acceleration (tangential) = a_t = r α = 1.0 * 5.0 = 5 m/sec²
ω = 0 + α t = 5. 0 * 6.0 s = 30 rad/s
centripetal acceleration = a_r = v² / r = r ω² = 1.0 * 30² = 900 m/sec²
resultant acceleration a = √[5² + 900²] m/sec²
linear acceleration (tangential) = a_t = r α = 1.0 * 5.0 = 5 m/sec²
ω = 0 + α t = 5. 0 * 6.0 s = 30 rad/s
centripetal acceleration = a_r = v² / r = r ω² = 1.0 * 30² = 900 m/sec²
resultant acceleration a = √[5² + 900²] m/sec²
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