A griup of mem decides to do a work in 15 days but 2 of them became absent if the rest of the group did the work in 25 days find the original number of men
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Let there be x number of men planning to work initially
Number of days taken by one man would be =15*x
Now as 2 men left
Number of days by one man would be =25(x-2)
As these are equal
15x=25x-50
10x=50
Or x=5
So 5 men started initially.
(Shortcut- M1D1=M2D2)
Number of days taken by one man would be =15*x
Now as 2 men left
Number of days by one man would be =25(x-2)
As these are equal
15x=25x-50
10x=50
Or x=5
So 5 men started initially.
(Shortcut- M1D1=M2D2)
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