Question

A grocer bought a number of fruit baskets for Rs. 800. Five baskets were lost in transport. He
sold the rest for Rs. 8 per basket more than what he paid for them and made a profit of
Rs.180 on his outlay. Find the number of baskets bought by him.
plese explain​

Answer 1

HeYa♡

Answer:

Let the number of baskets bought by grocer be x.

Given, cost price of x baskets = Rs 800

∴ Cost price of each basket  = rs 800/x

When five baskets were lost, then selling price of each remaining basket

= Rs  ( 800/ x +8 )

Selling price of ( x-5) baskets = Rs ( 800/x +8 ) (8-5)

Profit made by the grocer = Rs 180    (Given)

( 800/ x +8 )  (x-5)-800=180   [ profit= SP-CP]

= 8 ( 100 + x / x )  (x-5) = 800 + 180 = 980

⇒ 2 (100 + x) (x – 5) = 245 x

⇒ 2x2 + 190x – 1000 = 245 x

⇒ 2x2 – 55x – 1000 = 0

⇒ 2x2 – 80x + 25x – 1000 = 0

⇒ 2x(x – 40) + 25 (x – 40) = 0

⇒ (2x + 25) (x – 40) = 0

⇒ 2x + 25 = 0  or  x – 40 = 0

⇒ x= -25/2 or x = 40

∴ x = 40          (Number of baskets cannot be negative)

Thus, the number of baskets bought by the grocer is 40.

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Answer 2

Answer:

Let the number of baskets bought by grocer be x.

Given, cost price of x baskets = Rs 800

∴ Cost price of each basket

When five baskets were lost, then selling price of each remaining basket



Profit made by the grocer = Rs 180    (Given)



⇒ 2 (100 + x) (x – 5) = 245 x

⇒ 2x2 + 190x – 1000 = 245 x

⇒ 2x2 – 55x – 1000 = 0

⇒ 2x2 – 80x + 25x – 1000 = 0

⇒ 2x(x – 40) + 25 (x – 40) = 0

⇒ (2x + 25) (x – 40) = 0

⇒ 2x + 25 = 0  or  x – 40 = 0



∴ x = 40          (Number of baskets cannot be negative)

Thus, the number of baskets bought by the grocer is 40.