Math, asked by 12ishika34, 10 days ago

A grocer bought sugar worth of ₹4500. He sold one-third of it at a gain of 10%. At what gain per cent must the remaining sugar be sold to have a gain of 12% on the whole ?

Answers

Answered by midhunrnair04
1

Answer:

Overall gain = 12%

Gain % =

CP

SP−CP

×100

⇒12=

4500

SP−4500

×100

⇒SP=5040Rs

a) sold

3

1

rd

at gain of 10%

Gain % =

(4500/3)

SP−(4500/3)

×100

⇒10=

1500

SP−1500

×100

⇒SP

1

=1650Rs

SP

2

=SP−SP

1

=5040−1650

=3390Rs

CP=

3

2

×4500=3000Rs

Gain % =

3000

3390−3000

×100

=

30

390

=13%

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Answered by vaibhav13550
1

Step-by-step explanation:

Net worth of total sugar =Rs 4500.

1/3 of total sugar =1/3*4500=1500

10% of 1500=150.

So, he get RS 1500+150=1650 when he sold

1/3 of total sugar at 10% profit. He must gain 12% profit on total sugar

So, total sugar sold at rs4500+540= rs 5040

He had already gained rs 1650

so, now he want rs 5040-1650=rs 3390 he had left with sugar worth rs 4500-1500=3000

Now, let the gain percent on 2/3 of sugar be X

so, x% of 3000=3390-3000

x/100*3000= 390

x*30=390

x = 390/30 x = 13

Therefore, he must sold the remaining sugar at 13% gain so as to get 12% gain on total sugar.

Hope you get the correct answer.

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