Math, asked by Titli188, 1 year ago

A grocer earns a profit of rs.1 by selling one sketch pen and incurs a loss of 40 paise per eraser while selling erasers of old stock. In a particular week, she earns neither profit nor loss. If she sold 40 sketch pend, how many erasers did she sell?

Answers

Answered by maya51
7
Given that when one pencil is sold, the shopkeeper gets a loss of 40 paise and on selling 1 pen the shop keeper get a profit of Re 1
(1) 
If she sold 45 pens then the profit made by her = 45 x 1 = Rs 45 rupees.
Given that she got a loss of Rs 5.
This implies that means she sold some pencils. Hence she got loss on selling those pencils.
On selling those pencils She got a loss of Rs 50 (Since already she got profit Rs 45)
Let the number of pencils sold be x.
On selling 1 pencil, loss incurred = 40 paise
On selling x pencils, loss incurred = Rs 50
                                                                  = Rs 5000
Hence (1x 5000) = 40x
⇒ x = 5000/40 = 125
Thus number of pencils sold in the month is 125.
Answered by nafibarli789
0

Answer:

The number of pencils sold in the month exists at 125.

Step-by-step explanation:

Given:

When one pencil exists sold, the shopkeeper obtains a loss of 40 paisa and on selling 1 pen the shopkeeper gets a profit of Rs. 1.

she got a loss of Rs 5.

Step 1

If she sold 45 pens then the profit earned by her

= 45 * 1 = Rs 45 rupees.

On selling pencils she got a loss of Rs 50 (Since she got profit Rs 45)

Step 2

Let the number of pencils sold be x.

On selling 1 pencil, the failure incurred = 40 paisa

On selling x pencils, loss incurred = Rs 50 = Rs 5000

Therefore, (1 * 5000) = 40x

⇒ x = 5000/40 = 125

Hence, the number of pencils sold in the month = 125.

#SPJ2

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