Math, asked by stonearch30, 10 months ago

A grocer has a sale of Rs. 4212, Rs. 4164, Rs. 4728, Rs. 4626 for four consecutive months. How much
sale must he have in the fifth month so that he gets an average sale of Rs. 4800 ?
[ ]
a) 6250
b) 6270
c) 5850
d) 5870​

Answers

Answered by Swarup1998
19

Given: A grocer has a sale of Rs. 4212, Rs. 4164, Rs. 4728, Rs. 4626 for four consecutive months.

To find: How much sale must he have in the fifth month so that he gets an average sale of Rs. 4800?

Solution:

  • Let the sale be x

  • The total sale of five months is
  • = Rs. (4212 + 4164 + 4728 + 4626 + x)
  • = Rs. (x + 17730)

  • Then average for five months is
  • = Rs. (x + 17730)/5

By the given condition,

  • (x + 17730)/5 = 4800
  • or, x + 17730 = 24000
  • or, x = 24000 - 17730
  • or, x = 6270

Therefore, he must have a sale of Rs. 6270 in the fifth month so that he gets an average sale of Rs. 4800.

Answer: Option b) 6270

Answered by scs550265pdty
2

Answer:

6270

Step-by-step explanation:

A=S/N

A=4212+4164+4728+4626+x/5

A=4800

17330+x=24000

x=24000-17730

x=6270

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