Math, asked by suga78, 1 year ago

A grocer purchased 60kg of butter at the rate of ₹150 per kg .He sold 1/3 of it at a loss of 6%.At what price per kg should he sell the remaining butter so as to gain 10%on the whole deal?​

Answers

Answered by Anonymous
45

Answer:

Step-by-step explanation:

cost price of butter = 60*150=9000

1/3rd butter = (1/3)*60=20kg

s.p. of 20 kg butter = 3000*94/100=2820

gain on whole deal= 10%

S.P. = 9000*110/100=9900

remaining butter  = 40 kg

price he should sell = 9900-2820= 7080

per kg he should sell= 7080/40=177

Answered by Amanutkarsh
14

Total Amount of butter = 60 kg

Total CP of butter = ₹(150×60)

Sold \:  \:  \: Butter =  \frac{60}{3}  = 20kg \\  \\ its \: cp \: was \:  Rs \: (150 \times 20) = Rs. \: 3000

.°.  \: SP \:  \: at \:  \: 6 \: \% \:  loss =  \frac{100 - loss}{100}  \times cp =  \frac{100 - 6}{100}  \times 3000 =  \frac{94 \times 3000}{100}   = 94 \times 30 = Rs.2820\\

Now,  \\ Wished \:  \: SP =  \frac{100 + 12}{100}  \times 9000 =  \frac{112 \times 9000}{100}  = 112 \times 90 \\  =Rs. \: 10080

Now, Grocer need to sell the remaining butter i.e 40 kg at some rate which would allow him to earn ₹ 7260 as his selling price.

So,

cp \: of \: 40 \: kg \: butter = Rs.(150 \times 40) = Rs.6000 \\  \\ sp  = 7260 \\  \\  \frac{100 + gain\%}{100}  \times cp = 7260 \\  \\  \frac{100 + gain\%}{100}  \times6000 = 7260 \\  \\ (100 + gain\%) \times 60 = 7260 \\  \\ 100 + gain\% =  \frac{7260}{60}  = 121 \\  \\ gain\% = 121 - 100 \\ \\  gain\% = 21\%

HOPE IT HELPED.....MARK ME BRAINLIEST !!!!!!!!

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