Math, asked by tesla6978, 9 months ago

A grocer sells half of the eggs that he has and another half an egg to Anurag. Then he sells half of the balance egg and another half an egg to Deepak. Then he sells half of the balance eggs and another half an eggs to Shivani. In the end he is left with just 7 eggs and he claims that he never broke an egg. How many eggs did he start with?

Answers

Answered by Anonymous
0

Given:

People to whom eggs sold = 3

Remaining eggs = 7

To Find:

Eggs at the beginning

Solution:

Let the number of eggs with grocer be =  x

Thus, according to the question

Eggs sold to Anurag = ( x/2 + 0.5),

Similarly, eggs sold to Deepak = ( x/2 + 0.5),

Eggs sold to Shivani = ( x/2 + 0.5),

As per the question, combining the equations -

(x/2 + 0.5) + 1/2( x/2 + 0.5)+ 1/2(x/2 + 0.5) +7

x = 7x + 63 = 8X

= x = 63

Answer: The grocer is left with 63 eggs.

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