A grocer uses a weighing balance in which one pan
weighs 0.5 kg and the other 0.75 kg. He puts a
certain quantity of food grains in 0.5 kg pan and
finds the weight (in kg) as a two-digit number.
However, as the customer insists, he puts it in
0.75 kg pan. Now the indicated weight is 9.5 kg
more than the weight which is obtained by reversing
the digits of previous weight. Which of the following
cannot be the actual weight (in kg) of the
food grains?
(A) 43.25
(B) 36.25
(C) 41.5
(D) More than one of the above
need the solution for this
Answers
Answer:
D is right as 43.25 is only fits
Step-by-step explanation:
Solution :Let the actual weight of food grains be ‘w’.Case I:If it is kept in the pan of weight 0.5 kgTotal weight (including that of food grains)=w + 0.5
On the other side of the balance let ‘xy’ be the indicated weight.
Hence, w + 0.5 = 10x + y + 0.75 ...(1)
Case II:If food grains are kept in the other pan of the balance
w + 0.75 = 10y + x + 9.5 + 0.5 ...(2)
(2) – (1) gives 0.25 = 9(y - x) +9.25 9(x - y) = 9
x – y = 1 ...(3)
Now,1. w = 10x + y + 0.25 .. first weight is interger (10X +Y) -> So, the actual weight w = 10x + y + 0.25 So, in the actual weight the decimal part must be 0.25. And in the integral part, the ten’s digit should be one more than the unit’s digit. X>Y
Both these conditions are satisfied for (A), not for choices (B) and (C)Ans: Choice D