Question

A groocer buys a certain number of apples for Rd.960.he retained three scores of apple with him and sold the remaining for .Rd. 800, gaining Rd.2 per apples. How many apples did they buy?

Answer 1

Given :

The total price of apples = Rs 960

The number of apples retained out of apples purchased = 3

The price at which rest apples sold = Rs 800

The Gain amount = Rs 2 per apples

To Find :

The number of apple bought

Solution :

Let The number of apples bought initially = n apples

So, At Rs 960, n numbers of apples were bought

i.e cost price of n apples = Rs 960

And

Number of apple retained =  3

Selling price of  3 apples = s.p = Rs 800

∵  Gain = Selling price  - cost price

Or,  Rs 2 per apples = Rs 800 × (3) - Rs 960 × n

i.e  Rs 2 × n = Rs 800 × (  n - 3 ) - Rs 960 × n

Or,  2 n =  800 n - 2400 - 960 n

Or,  2 n = - 160 n - 2400

Or,  160 n - 2 n = 2400

Or,  158 n = 2400

∴             n = $\dfrac{2400}{158}$

i.e           n = 15

Hence, The number of apples did bought is 15  Answer