A ground is in the shape of rectangle of length 30m and width 20 m inside the lawn there is a lane pf uniform width 2m bordering the ground .the area of lane in m^2 is
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Area of the lane = 184 m²
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Solution :-
Length of the rectangular ground = 30 m
Breadth of the rectangular ground = 20 m
Area of the rectangular ground = L*B
⇒ 30*20
= 600 sq m
Given that the lane of uniform width 2 m bordering the ground.
Then,
Length of the inner rectangular portion = 30 - (2 + 2)
= 30 - 4
= 26 m
Breadth of the inner rectangular portion = 20 - (2 + 2)
= 20 - 4
= 16 m
Area of the inner rectangular portion = 26*16
= 416 sq m
Area of the lane of uniform width of 2 m = Area of the rectangular ground - Area of the inner rectangular portion
⇒ 600 - 416
= 184 sq m
Answer.
Length of the rectangular ground = 30 m
Breadth of the rectangular ground = 20 m
Area of the rectangular ground = L*B
⇒ 30*20
= 600 sq m
Given that the lane of uniform width 2 m bordering the ground.
Then,
Length of the inner rectangular portion = 30 - (2 + 2)
= 30 - 4
= 26 m
Breadth of the inner rectangular portion = 20 - (2 + 2)
= 20 - 4
= 16 m
Area of the inner rectangular portion = 26*16
= 416 sq m
Area of the lane of uniform width of 2 m = Area of the rectangular ground - Area of the inner rectangular portion
⇒ 600 - 416
= 184 sq m
Answer.
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