A group consists of 12 persons, of which 3 are extremely patient, other 6 are extremely honest and rest are extremely kind. A person from the group is selected at random. Assuming that each person is equally likely to be selected, find the probability of selecting a person who is (i) extremely patient (ii) extremely kind or honest. Which of the above you prefer more.
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Answer:
i) 3/12=1/4
Step-by-step explanation:
ii). 8/12=2/3
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Probability of selecting a person who is extremely patient = 1/4
Probability of selecting a person who is extremely kind or honest = 3/4
Step-by-step explanation:
Total number of people = 12
Number of patient people = 3
Number of honest people = 6
Number of kind people = 12 - (6 +3) = 3
Probability of selecting a person who is extremely patient = 3/12 = 1/4
Probability of selecting a person who is extremely kind or honest = (6+3)/12 = 3/4
I prefer the probability of selecting a person who is extremely kind and honest as it has the higher probability.
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