A group consists of 12 persons, of which 3 are extremely patient, other 6 are extremely honest and rest are extremely kind. A person from the group is selected at random. Assuming that each person is equally likely to be selected, find the probability of selecting a person who is(i) extremely patient(ii) extremely kind or honest.Which of the above values you prefer more? Zigya
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probability of getting a extremely patient i=3/12 i.e 1/4
probability of getting extremely honest or kind is 9/12 i.e 3/4
probability of getting extremely honest or kind is 9/12 i.e 3/4
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Answer:
P(E) = No if possible outcome / total outcomes
1) 3/12= 1/4
2) 6+3/12= 9/12=3/4
I think honesty would be preferred more..
Hope it helped you..☺️
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