A Group consists of 4 couples in which each of the 4 persons have one wife each. In how many ways could they be arranged in a straight line such that the men and women occupy alternate positions?
A) 1152
B) 1278
C) 1296
D) None of these
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I think d .... none of these
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Answer:
A) 1152
Step-by-step explanation:
We have two cases of men and women arrangements such that they occupy alternate positions.
1st Case: MW MW MW MW MW
2nd Case: WM WM WM WM
Therefore, men will be arranged in 4! ways. The women can be arranged in 4P4 ways, either left or right of the men.
Therefore, the number of arrangements possible = 2(4! * 4P4) = 2(24 * 24) = 1152
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