Math, asked by Girijamma, 10 months ago

A group consists of 7boys and 5girls.Find the number of Ways in which a team of 5members can be selected so as to have at least one boy and girl combination​

Answers

Answered by 860
1

Answer:

Step-by-step explanation:

Answer:

770

Step-by-step explanation:

a group consists of 7 boys and 5 girls find the number of ways in which a team of 5 members can be selected so has to have atleast one boy and one girl​

Total members = 7  + 5 = 12

Total number of ways a team  of 5 can be created

= ¹²C₅

= 12!/(5!7!)

= 792

If only boys are selected then  ⁷C₅

= 7!/(5!2!)

= 21

If only girls are selected then  ⁵C₅

= 5!/(5!0!)

= 1

Number of ways at least one girl & one boys =  Total number - only boys - only Answer:

770

Step-by-step explanation:

a group consists of 7 boys and 5 girls find the number of ways in which a team of 5 members can be selected so has to have atleast one boy and one girl​

Total members = 7  + 5 = 12

Total number of ways a team  of 5 can be created

= ¹²C₅

= 12!/(5!7!)

= 792

If only boys are selected then  ⁷C₅

= 7!/(5!2!)

= 21

If only girls are selected then  ⁵C₅

= 5!/(5!0!)

= 1

Number of ways at least one girl & one boys =  Total number - only boys - only girls

= 792 - 21 - 1

= 770

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