A group consists of 7boys and 5girls.Find the number of Ways in which a team of 5members can be selected so as to have at least one boy and girl combination
Answers
Answer:
Step-by-step explanation:
Answer:
770
Step-by-step explanation:
a group consists of 7 boys and 5 girls find the number of ways in which a team of 5 members can be selected so has to have atleast one boy and one girl
Total members = 7 + 5 = 12
Total number of ways a team of 5 can be created
= ¹²C₅
= 12!/(5!7!)
= 792
If only boys are selected then ⁷C₅
= 7!/(5!2!)
= 21
If only girls are selected then ⁵C₅
= 5!/(5!0!)
= 1
Number of ways at least one girl & one boys = Total number - only boys - only Answer:
770
Step-by-step explanation:
a group consists of 7 boys and 5 girls find the number of ways in which a team of 5 members can be selected so has to have atleast one boy and one girl
Total members = 7 + 5 = 12
Total number of ways a team of 5 can be created
= ¹²C₅
= 12!/(5!7!)
= 792
If only boys are selected then ⁷C₅
= 7!/(5!2!)
= 21
If only girls are selected then ⁵C₅
= 5!/(5!0!)
= 1
Number of ways at least one girl & one boys = Total number - only boys - only girls
= 792 - 21 - 1
= 770
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