Question

A group of 3 adults and 10 children bought tickets to watch a dance performance. Each adults ticket cost $7 more than each child ticket. The group paid a total of $125. What was the cost of each child ticket?

Answer 1

Answer:

cost is 8

Step-by-step explanation:

let adult =x

children =y

3x+10y=125

Each adults ticket cost $7 more than each child ticket:- x=7+y

3x+10y=125

3(7+y)+10y=125

21+3y+10y=125

13y=125-21

13y=104

y=104/13

y=8

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Answer 2

Answer:

$8

Step-by-step explanation:

No. of adults = 3

No. of children = 10

Let Cost of ticket of one children = x

Cost of ticket of one adult = x + 7

Now, According to Question

\begin{gathered}3(x + 7) + 10x = 125 \\ \\ 3x + 21 + 10x = 125 \\ \\ 13x = 125 - 21 \\ \\ 13x = 104 \\ \\ x = \frac{104}{13} \\ \\ x = 8\end{gathered}

3(x+7)+10x=125

3x+21+10x=125

13x=125−21

13x=104

x=

13

104

x=8

Cost of one child ticket = $8

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