Question

A group of 3 students, the probability of 2 students not having the same birth day is 0.992. What is the probability that the 2 students have the same birth day?

Answer 1

Answer:0.008

Step-by-step explanation:

Answer 2

let E be the event of having the same birthday

P(E) =0.992

But P(E) +P = 1

P= 1-P(E)

= 1-P(E)

=1-0.992

=0.008

✧･ﾟ: *✧･ﾟ:*✧･ﾟ: *✧･ﾟ:*.・゜゜・.・゜゜・✧･ﾟ: *✧･ﾟ:*༶•┈┈⛧┈♛♛┈⛧┈┈•༶✧༺༻✧*:..｡o○　○o｡..:*