Math, asked by jackeliott1, 8 months ago

A group of 42 children all play tennis or football, or both sports. The same number play tennis as play just football. Twice as many play both tennis and football as play just tennis. How many of the children play football?

Answers

Answered by amitnrw
2

All Subjects = 10  , Hindi only  = 20 & Commerce only  = 15

Step-by-step explanation:

Economics   E = 125

Hindi    H  = 100

Commerce  C = 145

Economics only = 25

Economics & Hindi  = E ∩ H  = 30

Economics & Commerce  = E ∩ C  = 80

Hindi & Commerce  = C ∩ H  = 60

All subject  E ∩ H ∩ C  = ?

Economics only  = E - E ∩ H - E ∩ C  +  E ∩ H ∩ C

=> 25 = 125  - 30 - 80 + E ∩ H ∩ C

=> E ∩ H ∩ C = 10

Hindi only  =  H - E ∩ H - H ∩ C  +  E ∩ H ∩ C

=> Hindi only  =  100 - 30 - 60 + 10

=> Hindi only  = 20

Commerce only  =  C - E ∩ C - H ∩ C  +  E ∩ H ∩ C

=> Commerce only  =  145 - 80 - 60 + 10

=> Commerce only  = 15

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Answered by jefferson7
14

A group of 42 children all play tennis or football, or both sports. The same number play tennis as play just football. Twice as many play both tennis and football as play just tennis. How many of the children play football?

Step-by-step explanation:

We will assume:

Each child play at least one game

Children Play Tennis = T

Children Play FootBall = F

Children Play Both = B

Just FootBall = F – B

Just Tennis = T – B

The same number play tennis as play just football

=> F – B = T

Twice as many play both tennis and football as play just tennis

2B = T – B

=> T = 3B

F – B = 3B

=> F = 4B

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