Math, asked by sumanroy797, 11 months ago

A group of certain number of men can complete a job in 5 days. On every alternate day starting from second day
3 men are withdrawn from the job and on every alternate day starting from third day, 2 men are added to the job.
If the job is completed in 6 days, what is the number of persons who started the job?
(1) 10
(2) 12
(3) 15
(4) Cannot be determined
(5) None of these​

Answers

Answered by Anonymous
8

Answer:

Step-by-step explanation:Let the number of workers be X.

Then, the total work = 9X man days.

As per the given condition, number of workers starting with the first day will be X, X - 2, X - 1, X - 3, X - 2, X - 4, X - 3… and so on till 18 days. So separating the odd and even terms and adding (9X - 36) + (9X - 54) = 9X

=> X = 10

And please mark it as the brainliest.

Answered by choudhary21
10

Step-by-step explanation:

On every alternate day starting from second day

On every alternate day starting from second day3 men are withdrawn from the job and on every alternate day starting from third day, 2 men are added to the job.

If the job is completed in 6 days, what is the number of persons who started the job

Answer 10

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