Math, asked by insiyahr, 1 year ago

A group of labourers is hired to complete the work in 12 days, bit three of them do not come work . Find the original number of labourers in the group, if the remaining labourers completed the work in 15 days. Solve it step by step with applicable answer


insiyahr: It's an question of direct and inverse variation
insiyahr: You have do it by unitary method

Answers

Answered by siddhartharao77
50

Answer:

15

Step-by-step explanation:

Let the number of laborers be x.

According to the given condition,

x people do the work in 12 days.

(x - 3) can do the work in 15 days.

By unitary method:

x : (x - 3) = 15 : 12

12x = 15(x - 3)

12x = 15x - 45

3x = 45

x = 15.


Therefore, the original number of laborers = 15.


Hope it helps!

Answered by Siddharta7
6

Answer:

72

Step-by-step explanation:

total days to complete=12

Labour absent =3

days tool to complete the world=15

total Labour's in the group=?

days+days/5=total Labour

12+15/3 = 9

total Labour = 9 * 12

                     = 72.

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