A group of labourers is hired to complete the work in 12 days, bit three of them do not come work . Find the original number of labourers in the group, if the remaining labourers completed the work in 15 days. Solve it step by step with applicable answer
insiyahr:
It's an question of direct and inverse variation
Answers
Answered by
50
Answer:
15
Step-by-step explanation:
Let the number of laborers be x.
According to the given condition,
x people do the work in 12 days.
(x - 3) can do the work in 15 days.
By unitary method:
x : (x - 3) = 15 : 12
12x = 15(x - 3)
12x = 15x - 45
3x = 45
x = 15.
Therefore, the original number of laborers = 15.
Hope it helps!
Answered by
6
Answer:
72
Step-by-step explanation:
total days to complete=12
Labour absent =3
days tool to complete the world=15
total Labour's in the group=?
days+days/5=total Labour
12+15/3 = 9
total Labour = 9 * 12
= 72.
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