Question

a group of labourers promise to do a piece of work in 10 days but five of them become absent if the remaining labours complete the work in 12 days find the original number in the group?
Please answer​

Answer 1

Answer:

CASE 1:

as 12 men will do the work in -18 days.

so 1 man do the work in -12*8 days

CASE2:

15 is correct. Let W be the work. x be the original number of men.

eqn 1. W=12x

eqn 2. W=18(x-5)

Thus 12x=18x-90

Solving we get x=15

1 day work for x men=1/12*x

1 day work for x-5 men=1/18(x-5)

1/12*x=1/18(x-5)=15