Question

A group of labourers promises to do a piece of work in 10 days, but 5of them become absent. if the remaining labourers compete the work in 12 days, find their original number in the group ​

Answer 1

Answer:

6 days.

Step-by-step explanation:

'x' be no. of worker and 'y' be no. of days

x=5, y=12

x=k*1/y

5=k*12

k=60

2nd con: X=? y=10

x=k*1/y

x=60*1/10

x=6