A group of men decided to do a job in 8 days. But since 10 men dropped out after 1st day, 2 more men dropped out after 2nd day, 2 more men dropped out after 3rd day and so on, the job got completed at the end of 12th day. How many men were there at the beginning?
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0
Answer:
24 as it is in A.P-arithmetic progression
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3
Answer:
No. of Men * No. of days = Work Done
or,
N1*D1 = N2*D2
Lets assume there were x people in the beginning
For LHS
Total work = 8x
For RHS,
Work done on day 1 = x * 1 (where 1 is 1 day)
Work done on day 2 = (x-10) * 1
Work done on day 3 = (x-20) * 1
....
and so on
Work done on day 12 = (x-110) * 1
Summation gives us net work = 12x - 660.
8x = 12x - 660
This gives x = 165
Hope this answer helps you
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