a group of n students can be divided into equal groups of 4 with 1 student left over or equal groups of 5 with 3 students left over. what is the sum of the two smallest possible values of n?
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Answer: 46
Step-by-step explanation:
Multiples of 5 end in 5 or 0, so if there are 3 students in addition to the groups of 5, the ones digit will be 8 or 3.
Take away the 1 extra student when making groups of 4 and the multiple of 4 has to be 7 or 2.
Since multiples of 4 never end in 7, the two smallest multiples of 4 that fit the criteria are 12 and 32. Add back the one extra student to each number and n = 13 or 33.
13 + 33 = 46
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