A GROUP OF SOLDIERS WERE ASKED TO FALL IN LINE MAKING ROWS OF THREE. IT WAS FOUND THAT THERE WERE ONE SOLDIER EXTRA. THEN THEY WERE ASKED TO STAND IN ROWS OF THREE. IT WAS FOUND THAT THERE WERE LEFT TWO SOLDIERS. THEY WERE ASKED TO STAND IN ROWS OF SEVEN. THEN THERE WERE THREE SOLDIERS WHO COULD NOT BE ADJUSTED. AT LEAST HOW MANY SOLDIERS WERE THERE IN THE GROUP? ALSO EXPLAIN THE PROCESS.
Answers
Answered by
36
3 x 17 +1 = 52
5 x 10 + 2 = 52
7 x 7 + 3 = 52
Answered by
10
Answer:
52
Step-by-step explanation:
we can use try and error method
let no. of soldiers be x
3x+1=5x+2=7x+3
7X that no. which gives the remainder 3 and for 5X give remainder 2
so this like
3 x 17 + 1 = 52
5 x 10 + 2 = 52
7 x 7 + 3 = 52
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