Question

A group of students decided to make a project in statistics. They are collecting the heights in cms of the 51 girls in their class. They arranged the data in less than cumulative frequency distribution table.

1. What is the lower limit of the median class?
a. 145
b. 150
c. 155
d. 160

2. What is the upper limit of the modal class?
a. 145
b. 150
c. 155
d. 160

3. What is the mean of lower limits of median and modal class?
a. 145
b. 150
c. 155
d. 160

4. What is the width of the class?
a. 10
b. 15
c. 5
d. none of these

5. What is the median?
a. 149.03 cm
b. 146.04 cm
c. 147.03 cm
d. 148.03 cm​

Answer 1

Answer:

1.a

2.c

3.b

4.ç

5.idk

Step-by-step explanation:

hope helps tou

Answer 2

• The lower limit of the median class is equal to 145 .
• The upper limit of the modal class is equal to 150 .
• The mean of lower limits of median and modal class is equal to 145 .
• The width of the class is equal to 5 .
• The median of given data is equal to 149.03 .

Given :- A group of students decided to make a project in statistics. They are collecting the heights in cms of the 51 girls in their class. They arranged the data in less than cumulative frequency distribution table.

To Find :-

1. What is the lower limit of the median class ?

2. What is the upper limit of the modal class ?

3. What is the mean of lower limits of median and modal class ?

4. What is the width of the class ?

5. What is the median ?

Solution :-

From given data making normal table first :-

Height (in cm) ------- Fi

0 - 140 ---------------- 4

140 - 145 ------------- 11 - 4 = 7

145 - 150 ------------- 29 - 11 = 18

150 - 155 ------------- 40 - 29 = 11

155 - 160 ------------- 46 - 40 = 6

160 - 165 ------------- 51 - 46 = 5

Total ------------------- ⅀Fi = 51

Now, arranging the data in cumulative frequency distribution table :-

Height (in cm) ------- Fi ----------- CF

0 - 140 ---------------- 4 ------------- 4

140 - 145 ------------- 7 ------------ 11

145 - 150 ------------- 18 ---------- 29

150 - 155 ------------- 11 ----------- 40

155 - 160 ------------- 6 ----------- 46

160 - 165 ------------- 5 ----------- 51

Total ------------------- ⅀Fi = 51

Here , n = 51

So,

→ (n/2) = 25.5

Then,

Cumulative frequency greater than 25.5 is 29, corresponds to the class 145 - 150.

Therefore,

→ Class 145 - 150 is the median class.

Also, from data we have, highest frequency class = 145 - 150 = modal class .

So,

→ The lower limit of the median class = 145 (Ans.)

→ The upper limit of the modal class = 150 (Ans.)

→ The mean of lower limits of median and modal class = (145 + 145)/2 = 290/2 = 145 (Ans.)

4. The width of the class = 5 (Ans.)

Now,

• Median = l + [{(n/2) - cf} / f] × h

from data we have :-

• l = lower limit of median class = 145
• n = total frequency = 51
• cf = Cumulative frequency of class before median class = 11 .
• f = frequency of median class = 18 .
• h = size of class = 5 .

Putting all value we get :-

→ Median = 145 + [(25.5 - 11)/18] × 5

→ Median = 145 + (14.5/18) × 5

→ Median = 145 + (72.5)/18

→ Median = 145 + 4.027777

→ Median = 145 + 4.03

→ Median = 149.03 (Ans.)

Learn more :-

calculate the median and mode from the following income between (rs)100-200 100-300 100-400 100-500 100-600 no of person...

https://brainly.in/question/23585381

Some students of class X donated for the welfare of old age persons. The contributions are shown in the following distri...

https://brainly.in/question/17314012