Question

A group of which of the order 35 can have how many subgroups of order 7

Answer 1

35/7=5
hence 5 sub groups of order7

Answer 2

➡HERE IS YOUR ANSWER⬇

$number \: of \: subgroups \\ \\ = \frac{order \: of \: the \: group}{order \: of \: the \: subgroup} \\ \\ = \frac{35}{7} \\ \\ =5$

⬆HOPE THIS HELPS YOU⬅