Math, asked by sahoodev26, 1 month ago

a>0 and a+b+c=a+2b+4c=0,then quadratic expression ax^2+bx+c will attain it's minimum value at X=k,then k equals​

Answers

Answered by Anonymous
2

Answer:

Consider the equation, ax² + bx+c

Now if b² - 4ac < 0, then it does not have any real roots and hence it will not intersect the x axis at any point.

If a > 0 then y ax² + bx+c will lie completely above x axis and If a < 0 then y = ax² + bx+c will lie completely below x axis.

It is given that the above equation is always greater than zero, Or

ax² +bx+c > 0 for eR.

This can only occur is

b² - 4ac < 0 and a > 0.

Answered by MrNishhh
2

Answer:

Consider the equation, ax² + bx+c

Now if b² - 4ac < 0, then it does not have any real roots and hence it will not intersect the x axis at any point.

If a > 0 then y ax² + bx+c will lie completely above x axis and If a < 0 then y = ax² + bx+c will lie completely below x axis.

It is given that the above equation is always greater than zero, Or

ax² +bx+c> 0 for eR.

This can only occur is

b² - 4ac <0 and a > 0.

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