A gulab jamun, contains sugar syrup up to about
30% of its volume. Find approximately how much
syrup would be found in 45 gulab jamuns, each
shaped like a cylinder with two hemispherical ends
with length 5 cm and diameter 2.8 cm (see Fig. 13.15).
Answers
Answer:
Total h=5cm
length of the cylinder h=5−2.8=2.2
volume of gulab jamun=volume of cylinder+volume of 2
hemispheres.
volume=3πr
2
h+
3
4
πr
3
=
7
22
×1.4×1.4
3
(3×2.2+4×1.4)
=
3
6.16(12.2)
=
3
75.152
=25.05cm cube.
jamuns=45
Hence there are 45 gulab jamuns
volume=45×25.05=1127.2830 percentage of syrup.
volume =1127.28×
100
30
=338.184cmcube.
Step-by-step explanation:
Answer:
Step-by-step explanation:
r = d/2 = 2.8/2 = 1.4cm
Height of cylinder ( h ) + 2*r = 5
h = 5 - 2.8 = 2.2cm
Volume of Cylinder = πr^2h = 22/7*1.4*1.4*2.2 = 13.55cm^3
Volume of hemisphere = 2/3πr^3 = 2/3 * 22/7 * 1.4 * 1.4 * 1.4 = 5.75cm^3
Volume of 2 hemispheres = 2*5.75 = 11.5cm^3
Total Volume of gulab Jamun = 13.55 + 11.5 = 25.05cm^3
Volume of 45 gulab jamuns = (45*25.05)cm^3
Volume of syrup in 45 gulab Jamun = 30/100*45*25.05
= 338cm^3 ( approx )
Have a good day ^^
( P.S. - Gulab Jamuns are finger-licking good :) )