Question

a Gulab Jamun contains sugar syrup up to about 30 percentage of its volume find approximately how much syrup would be found in 45 Gulab Jamun each shaped like a cylinder with hemispherical ends with length 5 cm and diameter 2.8 CM​

Answer 1

Given:-

• Gulab gulab jamun simplex cylinder with hemispherical ends with length 5 cm and diameter 2.8
• Gulab jamun contains syrup syrup up to about 30 percentage

To find:-

• find approximately how much would be found in 45 gulab jamun..?

Solutions:-

• Radius (r) of cylindrical part = Radius (r) of hemispherical part = 2.8/2 = 1.4 cm.

Length of each hemispherical part = 5 - 2 × length of hemispherical part.

=> 5 - 2 × 1.4

=> 5 - 2.8

=> 2.2cm

Volume of one gulab jamun = Volume of cylindrical part + 2 × Volume of hemispherical part

=> πr²h + 2 × 2/3πr³ = πr²h + 4/3πr³

=> π × (1.4)² × 2.2 + 4/3 + 4/3π (1.4)³

=> 22/7 × 1.4 × 1.4 × 2.2 + 4/3 × 22/7 × 1.4 × 1.4 × 1.4

=> 22 × 0.2 × 1.4 × 2.2 + 4/3 × 0.2 × 1.4 × 1.4

=> 13.552 + 11.498

=> 25.05cm³

Volume of 45 gulab jamun

=> 45 × 25.05

=> 1127.25cm³

Volume of sugar syrup = 30%

=> 30/100 × 1127.25

=> 338.17cm³

=> 338cm³

Hence, the 45 gulab jamun is 338cm³

Answer 2

Answer:

$\LARGE{ \underline{\underline{ \pink{ \bf{Required \: answer:}}}}}$

★Total h = 5cm

★Length of the cyclinder h = 5 - 2.8 = 2.2

★Value of gulab jamun = Volume of cyclinder + Volume of 2 hemispheres

_______________________

$volume = 3πr²h + \frac{4}{3}πr³$

$= \frac{22}{7} \times 1.4 \times 1.4 \frac{(3 \times 2.2 + 4 \times 1.4)}{3}$

$= \frac{6.16(12.2)}{3}$

$= \frac{75.152}{3} = 25.05cm \: cube$

________________________

➜Jamuns = 45

Hence, there are 45 gulab jamuns:

➜Volume = $\boxed{\sf\red{45× 25.05 = 1127.2830}}$

Percentage of Syrup.

______________________

$volume = 1127.28 \times \frac{30}{100} =$

$\boxed{\sf\red{{388.184cm}^{3} }}$