Question

a gun fires 200 bullet per minute with muzzle speed of 600m/s if each bullet is of mass 20g then the amount of force needed to hold the gun in position is :​

Answer 1

Answer:

Force = Change in momentum /time

          = $\frac{Number of bullets per second X Mass of bullet X(in g) X Velocity}{1000}$

          = $\frac{200 X 20 X 600}{1000}$

          = 2400N