Question

A gun fires a bullet at a speed of 140m/s.If the bullet is to hit a target as the same level as the fun and at 1 km distance,the angle of projection may be

Answer 1

we know that range R = u^2sin2 tetha / g

1km = 1000m

1000 = 140×140 sin2 tetha / 9.8

sin2 tetha = 1000×9.8/140×140

sin2 tetha = 1/2 = sin 30°

tetha = 15
The angle of projection = 15°

:)

Answer 2

Explanation:

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