Question

A gun fires a bullet at a speed of 140ms. If
the bullet is to hit a target at the same level as
the gun and at 1km distance, the angle of
projection may be
1) 60° or 30 degree
2) 40° or 50°
4) 20° or 70°
3) 150 or 75degree

Answer 1

Answer:

Given that range, R=1 km=1000 motor

u=140 m/s

but R=

g

u

2

sin2θ

putting g=9.8 m/s

2

we get sin2θ=

u

2

Rg

=

140×140

1000×9.8

sin2θ=0.5⇒2θ=30

o

⇒θ=15

o

or 90−15=75

o

Answer 2

Explanation:

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