Question

a gun fires a bullet horizontally from a height of 20m velicity of the bullet is 900m/s. how long does the bullet stay in air. ​

Answer 1

Explanation:

Correct option is

A

-0.25 m s−1

Initial momentum of the system  Pi=0

Given:  Mbullet=0.02 kg      Vbullet=100 m/s         Mgun=8 kg

Let the recoil velocity of gun be V.

Applying the conservation of linear momentum :  Pf=Pi

Or   MgunV+MbulletVbullet=0

Or   8V+0.02×100=0

⟹ V=−0.25 m/s

Answer 2

Answer:

1809 m

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