a gun fires a bullet of 25 kg with velocity 200 m/s.i f the mass of gun is 5 kg,t hen what is the recoil velocity of gun
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Answer :-
1000 m/s
Given :-
Mass of bullet (m₁) is 25 kg
Velocity of bullet(v₁) is 200 m/s
Mass of gun is (m₂) 5kg
Recoil of velocity of gun ? (v₂)
Explanation:-
As we know that,
From law of conservation of momentum,
m₁v₁= m₂v₂
Substituting the values to get the Recoil of velocity of gun (v₂)
25 ×200 = 5 × v₂
5 × 200 = v₂
v₂ = 1000 m/s
So, recoil of velocity of the gun is 1000 m/s
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