Question

A gun fires a bullet of mass 100g horizontal at 50m/s at a fixed target of soft wood. The bullet penetrates 50cm into target. Calculate time taken by the bullet to come to rest in the wood...The average retarding force exerted by the wood on the bullet​

Answer 1

Answer:

Mass of the bullet is mb=100gm=0.1Kg

Initial velocity of bullet u=50m/s

Final velocity is v=0m/s

(1) Initial momentum of bullet pi=mbub=5Kgm/s

(2) Final momentum of bullet pf=mbvb=0.1×0=0

(3)  Retardation occurred by the wooden block is

v²−u²=2as

−(50)²=2a(0.5)

a=−2500m/s2

(4) Resistive force

F=ma

=0.1×−2500

=2500N

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