A gun fires a bullet of mass 50 g. The bullet moving with a velocity of 100m/s strikes a sand bag and gets embedded after travelling 10cm.calculate
1.the resistive force exerted by the sand on the bullet and 2.the time taken by the bullet to come to rest
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Hi dear brother @Shreyansh2929....
Hope this ans may help u..
Mass of bullet (m) = 50 g = 0.050 kg
initial velocity of bullet (u) = 100m/s
distance travelled by bullet (s) = 10 cm = 0.1 m
We know ,
v² - u² = 2 as
⇒0 - (100)² = 2 x a x 0.1
⇒-1000 /0.1 = 2a
⇒-10000 = 2a
⇒a = - 5000 m/s²
resistive force = m x a
= 0.05 x(- 5000)
= - 250 N
For to know the value Time taken ...
We know v = u + at
⇒0 = 100 - 5000 t
⇒-100 /5000 = t
⇒t = 0.02 seconds
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Thanx 4 the question.
shreyansh2929:
CORRECT ANSWER
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