Question

A gun fires a bullet of mass 50 g with a velociy of 30 m//s. Due to this, the gun is pushed back with a velocity of 1 m//s, then the mass of the gun is :

Answer 1

Answer:

1.5 kg

Explanation:

Given:-

$M_{bullet}$ = 0.05 kg

$v_{bullet}$ = 30 m/s

Recoil velocity of gun, V = 1 m/s

Using V=$\frac{M_{bullet}v_{bullet} }{M_{gun} }$

∴ 1 = $\frac{0.05 X 30}{M_{gun} }$

⇒ $M_{gun}$ = 1.5 kg

Answer 2

Answer:

mass of bullet=50g=0.05kg

velocity of bullet=30m/s

momentum of bullet=0.05×30 kg.m/s

=0.5 kg.m/s

velocity of gun = 1 m/s

Let the mass of gun be m kg

momentum of gun =m×1 kg.m/s

m×1 = 0.5

m=0.5 kg

Explanation:

conservation of momentum