Physics, asked by saurav5076, 10 months ago

a gun fires a bullet of mass 50 gm , moving with a valocity of 100 m/sec stricks with a wooden plank and come to rest in 0.05 second calculate.
(1) force exercted by the wooden plank on the bullet.
(2) the distance of penetration of the bullet on the wooden plank .​

Answers

Answered by Hehuiwi
0

Answer

Explanation: may be like that is your answer

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Answered by shaunprem004
2

Answer:

Explanation: m=0.05 kg (50 gm to kg)

                       u=100 m/s

                       v=0 m/s

                       t=0.05 s

                      a=?

        a=v-u/t

       a=0-100/0.05

       a=-2000 m/s^2

      F=ma

      F=0.05*2000

      F=100 N

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