A gun fires a small bullet with kinetic energy K,then kinetic energy of the gun while recoiling is?
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it is equal to k according to newtons third law every action has equal and opposite reaction
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let the mass of the bullet and the mass of the gun be m1 and m2 respectively.
let the velocities of bullet and gun be v1 and v2 respectively
According to the law of conservation of momentum -
m1v1 = m2v2
⇒ 1/2 *m2
= 1/2 *m1*v1*v2 ( multiplying both sides by 1/2 and v2)
⇒ Kinetic energy of gun = 1/2*m1*v1*v2
let the velocities of bullet and gun be v1 and v2 respectively
According to the law of conservation of momentum -
m1v1 = m2v2
⇒ 1/2 *m2
⇒ Kinetic energy of gun = 1/2*m1*v1*v2
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