Physics, asked by Maychidinma8899, 5 months ago

A gun fires at an angle of elevation 30° with velocity of 2×10^3 .Find the range and how high will the shell rise

Answers

Answered by sayedzeenu
0

Answer:

I hope it will help you

Explanation:

Vo = 2000m/s @ 30o.

Xo = 2000*cos30.

Yo = 2000*sin30 = 1000 m/s.

Range = Vo^2*sin(2A)/g.

Vo = 2000 m/s.

2A = 60o.

g = 9.8m/s^2.

hmax = (Y^2-Yo^2)/2g.

hmax = (0-10^6)/19.6 = 51,020 m.

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