A gun having mass 20kg fires a bullet of mass 400g with a velocity of 100m/s What will be the recoil velocity of the gun
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Answer:
2 m/s
Explanation:
m1(gun)=20 kg
m2(Bullet)=400 g=0.4 kg
v2(Velocity of bullet)=100 m/s
According to conservation of linear momentum,
m1v1=m2v2
v1=40/20
v1=2 m/s
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