A gun is fired in the air at a distance of 900m from a person. He hears the sound of the gun after 3 seconds. What is the speed of sound?
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Hey there!!
Here's your answer!!!
given,
![d = 900 \: m d = 900 \: m](https://tex.z-dn.net/?f=d+%3D+900+%5C%3A+m)
![t = 3 \: s t = 3 \: s](https://tex.z-dn.net/?f=t+%3D+3+%5C%3A+s)
we know that
![v = 2d \div t v = 2d \div t](https://tex.z-dn.net/?f=v+%3D+2d+%5Cdiv+t)
therefore,
![v = 2 \times 900 \div 3 v = 2 \times 900 \div 3](https://tex.z-dn.net/?f=v+%3D+2+%5Ctimes+900+%5Cdiv+3)
![= > 600 \: mtrs \: per \: sec = > 600 \: mtrs \: per \: sec](https://tex.z-dn.net/?f=+%3D++%26gt%3B+600+%5C%3A+mtrs+%5C%3A+per+%5C%3A+sec)
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Here's your answer!!!
given,
we know that
therefore,
hope it was helpful!!
please mark as beainliest!!!
please follow me if you want me to answer more of your questions!!!
✌✌
Answered by
0
Answer:
660
Explanation:
d=900m
t = 3 \: st=3s
we know that
v = 2d \div tv=2d÷t
therefore,
v = 2 \times 900 \div 3v=2×900÷3
= > 600 \: mtrs \: per \: sec=>600 mtrs persec
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