Question

A gun is fitted on platform moving with velocity.
V = 10 m/s. A bullet is fired from the gun with
muzzle velocity v, = (40î + 20ſ) m/s with respect
to the platform. Then the horizontal range of
projectile is
(1) 100 m
(2) 400 m
(3) 200 m
(4) 300 m​

Answer 1

answer : option (3) 200m

explanation : velocity of platform, $v_p$ = 10 i m/s

velocity of bullet with respect to platform, $v_{bp}$ = (40 i + 20 j) m/s

so, velocity of bullet with respect to ground, $v_b=v_{bp}+v_p$

or, $v_b$ = 40i + 20j +10i

= 50i + 20j

velocity of bullet in horizontal direction, ux = 50m/s

velocity in vertical direction, uy = 20m/s

now, horizontal range, $R=\frac{2u_x.u_y}{g}$

= {2(50)(20)}/10

= 200 m

hence, horizontal range = 200m

Answer 2

Explanation:

refer to attachment.....