Question

A gun mass 10000kg fires a shot of mass 50 kg with velocity of 250ms-1 find the velocity of recoil of gun

Answer 1

Answer:

a gun mass 10000kg fries a shot of mass 50 kg who

Explanation:

it will decress 10000 Kg to50

Answer 2

A gun of mass 10000 kg fires a shot:

Given data:

• Mass of the gun($m_{1}$)= 10000 kg.
• Mass of the shot($m_{2}$) = 50 kg.
• Velocity of the shot($v_{2}$)= 250 m/s

Let the velocity of recoil or shot be $v_{2}$

• Total momentum of the gun and the shot is given by,

                           $m_{1}v_{1}+m_{2}v_{2}$

• As the gun and the shot were at rest before firing, the total momentum is equal to zero.
• Hence by Law of conservation of momentum, it can be written as

 

                                  $m_{1}v_{1}+m_{2}v_{2}=0\\10000*v_{1}+50*250=0\\v_{1}=-12500/10000\\v_{1}=-1.25 m/s$

The velocity of recoil is 1.25 m/s.