Question

A gun mass of 3kg fires of a bullet mass 30kg the bullet takes 0.003 and velocity 100m/s caculate the force exerted on gunman due to recoil of gun

Answer 1

Force exerted on man = 30 x 100 / 0.003
force = 1000000 N

Answer 2

Explanation:

Force which is exerted on a man =30×100÷0.003

==>Force=1000000

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