Question

A gun of mass 1 kg fires 4 bullets per sec each
of mass 20 g with a velocity 300 m s-1. The force
required to hold the gun is​

Answer 1

MASS OF THE BULLET=10 KG

AND VELOCITY OF BULLET=300 ms^-1

THEREFORE FORCE ON BULLET=10*4*300

= 12000

FORCE IS DIRECTIONALLY PROPORTIONAL TO RATE OF CHANGE OF MOMENTUM

THEREFOR PER SECOND A BULLET APPLIES A FORCE OF MV

ACCELARATION =V-U/T

U-0

T = 1

THEREFORE A-V

THEREFORE FORCE BY ONE BULLET=MV

= 20*300

= 6000

Answer 2

force = mass× acceleration

so force = 24 N

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