Physics, asked by paechuarsenal9490, 1 year ago

A gun of mass 1 kg fires a bullet of mass 1 gram with a velocity of 1 m per second inverse the recoil velocity of the gun is

Answers

Answered by Anonymous
11

Ram Ram Ji................

Here is your answer.................

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Answered by muscardinus
8

The recoil velocity of the gun is 0.001 m/s.

Explanation:

It is given that,

Mass of the gun, m = 1 kg

Mass of the bullet, m' = 1 g = 0.001 kg

Velocity of the bullet, v' = 1 m/s

We need to find the recoil velocity of the gun. Let v is the velocity of the velocity of the gun. It can be calculated using conservation of momentum as:

mv+m'v'=0

v=\dfrac{m'v'}{m}

v=\dfrac{0.001 \times 1}{1}

v = 0.001 m/s

So, the recoil velocity of the gun is 0.001 m/s. Hence, this is the required solution.

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