a gun of mass 10 kg fires A bullet of mass 50g with a velocity 600m/s with what velocity does the gun recoil
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Explanation:
Given
a gun of mass 10 kg fires A bullet of mass 50 g with a velocity 600 m/s with what velocity does the gun recoil
- When a person shoots a bullet Recoil velocity is the backward velocity. The person who shoots will experience a backward push and recoil velocity is due to conservation of linear momentum of the system.
- Now initial momentum of the system along with gun and bullet is 0
- So final momentum of the system = momentum of the gun and momentum of the bullet
- = M v’ + mv where v’ is the recoil velocity
- Now applying conservation of linear momentum we get
- M v’ + mv = 0
- So v’ = -(mv) / M negative sign indicates direction of velocity of gun is opposite to direction of velocity of the bullet
- Now m = 50 g = 0.05 kg
- Mass of gun M = 10 kg
- Velocity of bullet = 600 m / s
- So v’ = - (mv) / M
- = - (0.05 x 600) / 10
- = - 3 m / s
Reference link will be
https://brainly.in/question/6554854
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