Question

A gun of mass 1000 kg fires a projectile of mass 1 kg with a horizontal velocity of 100 m/s. The velocity of recoil of the gun in the horizontal direction is (a) 5 m/s (b) 0.1 m/s (e) 15 m/s (d) 20 m/s​

Answer 1

A gun of mass 1000 kg fires a projectile of mass 1 kg with a horizontal velocity of 100 m/s.

• Let final velocity of gun be 'v'.

Now, we can apply the principle of CONSERVATION OF LINEAR MOMENTUM:

$\therefore P_{i} = P_{f}$

$\implies \: m_{1}u_{1} + m_{2}u_{2} = m_{1}v_{1} + m_{2}v_{2}$

$\implies \: (1 \times 0) + (1000 \times 0) = (1 \times 100) \times (1000v)$

$\implies \:0= (1 \times 100) \times (1000v)$

$\implies 1000v = - 100$

$\implies v = - 0.1 \: m {s}^{ - 1}$

So, recoil velocity of gun is 0.1 m/s.

Answer 2

Explanation:

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